IIT-JEE - Solutions- 2009 Paper 2
|
IIT-JEE
2009: Chemistry Paper 1 |
SECTION
I
Q
1. The Henry's law
constant for the solubility of gas in water at 298 K is
1.0 * 10 5 atm. The mole fraction of
in air is 0.8. The number
of moles of
from air dissolved in 10 moles of water at 298 K and 5 atm
pressure is
(A)
(B)
(C)
(D)
Ans
Q
2. The correct acidity
order of the following is
(A) (III) > (IV) > (II) >
(I)
(B) (IV) > (III) > (I) >
(II)
(C) (III) > (II) > (I) >
(IV)
(D) (II) > (III) > (IV) >
(I)
Ans.
An acid is more acidic and electron withdrawing
group increases acidic character.
Q
3. The reaction of
with X
leads selectively to
. The
X
(A) Dry
(B) A mixture of
and N
(C) Moist
(D) in the presence of
aqueous
Ans.
with limited supply of air gives
Q 4. Among cellulose, poly(vinyl chloride), nylon and natural rubber, the polymer in which the intermolecular force of attraction is weakest is
(A) Nylon
(B) Poly(vinyl chloride)
(C) Cellulose
(D) Natural Rubber
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IIT-JEE - Solutions- 2009 Paper 2
