ANKIT PANDE said – Sat, 10 Oct 2009 13:42:09 -0000 ( Link )
A BUFFER OF PH9.26 MADE BY DISSOLVING X MOLES OF AMMONIUM SULPHATE AND .1 MOLE OF AMMONIUM INTO 100 ML SOLUTION .IF PKB OF AMMONIUM IS 4.74 ,CALCUTATE VALUE OF X.
- Actions
A BUFFER OF PH9.26 MADE BY DISSOLVING X MOLES OF AMMONIUM SULPHATE AND .1 MOLE OF AMMONIUM INTO 100 ML SOLUTION .IF PKB OF AMMONIUM IS 4.74 ,CALCUTATE VALUE OF X.
pOH = pKb + log [salt]/[base] then the answer comes out to be: 0.1 moles in 1000ml i.e. 0.01 moles in 100ml
Post Comments