rahulksinha said – Sat, 15 Aug 2009 13:30:59 -0000 ( Link )
If integration 0 to x :- f(x)sintdt = constant ; x~(0,2pie) and f(pie) = 2, find f(pie/2) ?
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definite integral (Question)
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djchalil said – Tue, 18 Aug 2009 13:37:47 -0000 ( Link )
integrn 0 to x; f(x)sintdt = Const., i.e, f(x)* integrn 0 to x;sintdt = const., i.e, f(x)(1-cos x) = const., hence, subst ‘pi’ in above eqn, we get, f(pi)2 = const., but f(pi) = 2, so, const = 4., subst ‘pi/2’ in old eqn once again, we get, f(pi/2)*1 = const = 4., so, f(pi/2) = 4.
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rishu _gupta said – Sat, 29 Aug 2009 18:44:31 -0000 ( Link )
What’s the answer. Is the answer 0.
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