rishu _gupta said – Thu, 06 Aug 2009 05:29:02 -0000 ( Link )
integrate under limits from 1/2 to 2 (1/x)*sin{x-(1/x)}dx
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definite integration (Question)
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djchalil said – Tue, 18 Aug 2009 13:45:19 -0000 ( Link )
In this Integration, since the limits are 1/2 and 2, i.e, reiprocal of each other & also, 1/x & x are coming, we substitute x=1/t. Let the question be ‘I’. After substituting x=1/t and simplifying (take care of the limits, it will change from 2 to 1/2, & dx= 1/t^2 dt),we get I = -I, hence, 2I=0. so, I=0.
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